x^2-20x+21=2

Solution for x^2-20x+21=2 equation:

Simplifying
x2 + -20x + 21 = 2

Reorder the terms:
21 + -20x + x2 = 2

Solving
21 + -20x + x2 = 2

Solving for variable 'x'.

Reorder the terms:
21 + -2 + -20x + x2 = 2 + -2

Combine like terms: 21 + -2 = 19
19 + -20x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
19 + -20x + x2 = 0

Factor a trinomial.
(1 + -1x)(19 + -1x) = 0

Subproblem 1
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Subproblem 2
Set the factor '(19 + -1x)' equal to zero and attempt to solve:

Simplifying
19 + -1x = 0

Solving
19 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + -1x = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -1x = 0 + -19
-1x = 0 + -19

Combine like terms: 0 + -19 = -19
-1x = -19

Divide each side by '-1'.
x = 19

Simplifying
x = 19
Solution
x = {1, 19}